(2c+1)(c^2-3c+2)=x

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Solution for (2c+1)(c^2-3c+2)=x equation: 


Simplifying
(2c + 1)(c2 + -3c + 2) = x

Reorder the terms:
(1 + 2c)(c2 + -3c + 2) = x

Reorder the terms:
(1 + 2c)(2 + -3c + c2) = x

Multiply (1 + 2c) * (2 + -3c + c2)
(1(2 + -3c + c2) + 2c * (2 + -3c + c2)) = x
((2 * 1 + -3c * 1 + c2 * 1) + 2c * (2 + -3c + c2)) = x
((2 + -3c + 1c2) + 2c * (2 + -3c + c2)) = x
(2 + -3c + 1c2 + (2 * 2c + -3c * 2c + c2 * 2c)) = x
(2 + -3c + 1c2 + (4c + -6c2 + 2c3)) = x

Reorder the terms:
(2 + -3c + 4c + 1c2 + -6c2 + 2c3) = x

Combine like terms: -3c + 4c = 1c
(2 + 1c + 1c2 + -6c2 + 2c3) = x

Combine like terms: 1c2 + -6c2 = -5c2
(2 + 1c + -5c2 + 2c3) = x

Solving
2 + 1c + -5c2 + 2c3 = x

Solving for variable 'c'.

Combine like terms: x + -1x = 0
2 + 1c + -5c2 + 2c3 + -1x = 0

The solution to this equation could not be determined.

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